Find Numbers with Even Number of Digits

Given an array nums of integers, return how many of them contain an even number of digits.

Input: nums = [12,345,2,6,7896]
Output: 2
Explanation: 
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.

Solution:

 public int FindNumbers(int[] nums) {
        
        int fCount=0;
        foreach(var item in nums){
            int count=0,number=item;
            
            while(number>0){
                number=number/10;
                count++;
            }
            
            if(count%2==0){
                fCount++;
            }
        }
        return fCount;
        
    }